|
|
|
Why Phil Mickelson
and the One Ball Rule cost the U.S. 2 holes at the
Presidents Cup...
Phil Mickelson somehow managed to lose
two holes for his team with one mistake
on Friday at the Presidents Cup. How?
Let’s try to explain.
On the seventh hole of his fourballs
(best ball) match taking with Zach
Johnson against Jason Day and Adam
Scott, Mickelson played a model of golf
ball different than the one he used to
start the match. That’s a violation of
Rule 33-1 in the Rules of Golf, as well
under Rule 5-1, defined as the One Ball
Rule as a Condition of Competition. It
means a player cannot use multiple
models of golf balls in an attempt to
gain an advantage as conditions change.
Typically, the match-play penalty for
violating a rule relating to playing the
wrong ball is the automatic
disqualification of violating player
from the hole on which the mistake was
discovered. In one-on-one match play,
that means the loss of a hole. After
consulting with a PGA Tour official,
Mickelson picked up his ball.
Johnson, flying solo, made par 5 on the
hole and lost to Jason Day’s birdie to
go 1 down in the match.
So, how then did the U.S. go 2 down in
the match?
Mickelson and Johnson were penalized
together for Mickelson’s Rule 5-1/33-1
infraction. A breach of a Condition of
Competition leads to a change in the
state of the match on which the breach
is discovered, up to two holes. Since it
was realized on the seventh, it was just
a one-hole adjustment. So the U.S. lost
the seventh twice, once in playing it
and another through an adjustment
penalty.
However, PGA Tour chief rules official
Mark Russell later told U.S. captain Jay
Haas that Mickelson actually could have
played out the hole, even with the wrong
ball, in fourball match play. An
official mistakenly gave Mickelson bad
information in saying he should pick up.
Under the Rules, however, there is no
recourse for Mickelson to remedy the bad
info, so the ruling stands — as wacky as
it sounds.
|
|
|
|
WebGolfClub.com
is Recognized by the
PGA of America
|
|
|
|
|